How 8086 microprocessor converts a logical address into physical address? Explain with example.
Logical address is expressed as the
location relative to the beginning of the program. It is defined by the user of
the microprocessor no need for calculation.
Physical address is defined as the
actual location of the process in the main memory it is allocated by the CPU.
Physical address = base address * 10h
+ offset address
For
example:
The physical address of 7A32: 0028H
is
7A32 * 10h = 7A320
7A320 + 0028 = 7A348 the physical
address is 7A348
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